Mathematics, 30.08.2021 17:00 kbell182005
The equation of a curve is given by y = px2 +qx+r. The line y = x+1 is a tangent to the curve.
(i) Showthat(q−1)2 =4p(r−1).
(ii) Given further that the curve has a minimum point at
3 1
− 2 , − 4 , show that
q = 3p and 4r = 9p − 1. Hence, find the values of p, q and r.
Answers: 3
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The equation of a curve is given by y = px2 +qx+r. The line y = x+1 is a tangent to the curve.
(i)...
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