The perimeter of a rectangular pool is 250 feet. The length is 3times longer than the width. What are the dimensions of the pool?

Length = 52m Width = 25m

Step-by-step explanation:

P = 2L + 2W = 154 meters

L = 2W + 2 Substitute and solve.

2(2W + 2) + 2W = 154 remove parentheses and combine like terms

4W + 4 + 2W = 154

6W + 4 = 154. Subtract 4 from both sides

6W = 150. Divide both sides by 6

W = 25 m

Therefore: L = 2W + 2 = 2(25) + 2 = 52m

check: P = 2(52) + 2(25) = 104 + 50 = 154m OK

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2