Given: m∠ACB = m∠ABC
Prove: ∠XCA = ∠YBA

Given that <ACB is congruent to <ABC we can infer that the triangle formed is an isosceles triangle. If B and C are both congruent and the distance from c and x and b and y are also congruent than the angles are congruent.

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl