B) 2x² - 4x + 3 = 0
a) x² + 3x – 10 = 0

you did not gave any information

other then equation

a. x = 2 , x = -5

b. no real roots

Step-by-step explanation:

a. x² + 3x – 10

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

= (x - 2) (x + 5)

x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

x = 2                                   x = -5

x = 2 , x = -5

b. 2x² - 4x + 3

This can't be solved because the equation has no real roots, and also the discriminant is negative.

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true