Using the segment addition postulate, find the value of x. JK = 3x - 4
KL = 5x + 6
JL = 9x - 8

When you say, J is between H and K, I am guessing you mean J is on the straight line joining H and K.

If this is the case it is a simple matter of adding the two segments: HJ and JK to get the overall length: HK.

HJ + JK = HK

3(X + 2) +(3X - 4) = 44

3X + 6 + 3X - 4 = 44

6X + 2 = 44

6X = 42

X = 7.

Step-by-step explanation:

hope it helps you friend ☺️

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: