If one of the angles of a triangle is 130 degree then the angle between the bisectors of the other two angles can be (a) 65° (b) 50°(c)145°(d)155°
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D) 155

Step-by-step explanation:

let <A, <B,<C are three angles in a triangle.

sum of the three angles in a triangle is 180degree.

<A+<B+<C=180

130+<B+<C=180 since one angle is given

<B+<C =180-130

<B+<C=50

(<B+<C)/2=25(1)after bisecting sum of the angles

required angle =180-25=155

d is correct answer

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

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