I need help with #65 to #70 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP… it is passed due

I need points sorry ignore this

All of the given questions(#65 to #70) are AP(s).

Formula to be used: a(n) = a(1) + (n - 1)d

Pronounced as:

nth term = 1st term + (n - 1)d, where d is the common difference.

*d = difference of any two consecutive terms.

65):

1st term = 2, d = 6 - 2 = 4

Therefore,

11th term = 2 + (11 - 1)4 = 42

66):

1st term = 5, d = 15 - 5 = 10

Therefore,

16th term = 5 + (16 - 1)10 = 155

67):

1st term = 19, d = 39 - 19 = 20

Therefore,

21st term = 19 + (21 - 1)20 = 419

68):

1st term = 8, d = 38 - 8 = 30

Therefore,

36th term = 8 + (36 - 1)30 = 1058

69):

1st term = 1/2, d = 1 - 1/2 = 1/2

Therefore,

101st term = 1/2 + (101 - 1)1/2 = 101/2

70):

1st term = 0.75, d = 1.50 - 0.75 = 0.75

Therefore,

151st term = 0.75 + (151 - 1)(0.75) = 113.25

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

4.08%

step-by-step explanation: