Find he change in the volume of a cube when the edge lengths all change by an amount dx

Hello,

Method 1:

V=x^3
dV=3x²*dx

Method 2:

V+dV=(x+dx)^3=x^3+3x^2dx+3xdx²+dx^3
V=x^3

V+dV-V=dV=3x²dx+3xdx²+dx^3
Since dx^3<<dx^2<dx , we forget dx^3 and dx^2
==>dV=3x²dx

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct