Necesito ayuda con este ejercicio de matematicas:
(3x-2)/4+5=(x+3)/2

x=12

Step-by-step explanation:

(3x-2)/4+5(x+3)/2

3x-2+20=2(x+3)

3x+18=2x+6

3x-2x=6-18

=x=-12

x = -12 not 12 as in previous response

Step-by-step explanation:

(3x-2)/4 + 5 = (x+3)/2 put terms on left and constants on right

(3x-2)/4 - (x+3)/2 = -5

multiply all terms by 4

(3x-2) - 2(x+3) = -20 now simplify by distributing -2 in second term

3x - 2 - 2x - 6 = -20 combine like terms

x -8 = -20 now add 8 to both sides

x = -12

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19