PROBABILITY QUESTION!!! PLEASE HELP Consider a collection of envelopes consisting of 1 red envelope​, 3 blue envelopes​, 2 green envelopes​, and 2 yellow envelopes. If one of the envelopes is selected at​ random, determine the probability that a blue or a green envelope is selected.
The probability of selecting a blue or a green envelope is:

Step-by-step explanation:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

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