Let h be a polynomial function. Which statements indicate that −3 is a zero of h ? Select all that apply. h(−3)=0 h of negative 3 is equal to 0h(0)=−3 h of 0 is equal to negative 3(x−3) is a factor of h open paren x minus 3 close paren is a factor of h(x+3) is a factor of h open paren x plus 3 close paren is a factor of hThe graph of h(x) shows an intercept at x=−3 The graph of h of x shows an intercept at x is equal to negative 3The graph of h(x) shows an intercept at y=−3 .The graph of h of x shows an intercept at y is equal to negative 3.

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

3

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1