What is the end behavior of the graph of f(x) = x5 – 8x4 + 16x3? The graph touches, but does not cross, the x–axis at x =
.

The graph of the function crosses the x–axis at x =
.

The graph touches, but does not cross, the x–axis at x = 4

The graph of the function crosses the x–axis at x = 0

Step-by-step explanation:

f(x) = x⁵ – 8x⁴ + 16x³

     =x³ (x² - 8x + 16)

     = x³ (x-4)²

f(x) = 0      x = 0 or x = 4

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^