6 (2 -6v)>-96 pls hurry

6(2-6v)>96

Step-by-step explanation:

step 1: distributive property

12-36v>-96

step 2: add like terms

12-36v>-96

(subtract 12 from both sides.)

-36v>-96-12

-36>-108

step 3: divide by coefficient which is -36

-36v/-36>-108/-36

v<3

(sign flips bc u r dividing by negative.)

Hope this helps   :)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: