One movie is 120 minutes long. Another is 100 minutes long. If both movies are started at 12 p. m., at what time will they start together again?

3:40 pm

Step-by-step explanation:

120 is 2 hours and 100 is 1 and 40 minutes

Given:

Time length of first movie = 120 min

time length of second movie = 100 min

start time = 12 pm

To find:

What time will they start together again

Steps:

for this question we have to find LCM of both of them,

120 = 2 * 2 * 2 * 3 * 5

100 = 2 * 2 * 5 * 5

LCM = 2 * 2 * 2 * 3 * 5 * 5

LCM = 4 * 2 * 3 * 5 * 5

LCM = 8 * 3 * 5 * 5

LCM = 24 * 5 * 5

LCM = 120 * 5

LCM = 600 min

600 min = 600/60 hr

              = 10 hours

Therefore, they will start again at 10 o'clock

Happy to help :)

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy