time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)
Answer from: Quest
5\16 x 2\5 = 10/80simplify to 1/80
Answer from: Quest
y/x of point b= y/x of point a
step-by-step explanation:
(i got the same question, this was the correct answer.)
Another question on Mathematics
Mathematics, 21.06.2019 19:30
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