Please help it’s due tomorrow

Step-by-step explanation:

1) m<CDN = m<CDE - m<NDE = 180-156 = 24°

2) m<KLV = m<KLM - m<VLM = 178-158 = 20°

3) m<UVW = m<UVT + m<TVW

172 = 21x+1+149x+1 = 170x+2

Subtract 2, 172-2 = 170x => 170 = 170x. So, x=1

4) m<ABC = m<ABN + m<NBC

100 = 2x+13+5x+17

100 = 7x+30

70 = 7x. => x=10

5) m<JKL = m<JKE +m<EKL

129 = x+88+43+x

129 = 2x+131

-2 = 2x => x=-1

m<JKE = x+88 = -1+88 = 87°

6) m<GHI = m<GHK + m<KHI

178 = x+40+x+162

178 = 2x+202

-24 = 2x => x=-12

m<GHK = x+40 = -12+40 = 28°

7) m<ABC = m<ABL + m<LBC

23x+8 = 29+21x-7

2x = 14 => x=7

m<LBC = 21x-7 = 21*7 - 7 = 147 - 7 = 140°

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2