12. Find a number t such that the line containing the points (t, -2)and (-3,5) is perpendicular to the line that contains the
points (3,7) and (5, 11).

t= 11

Step-by-step explanation:

Gradient of line that contains points (3, 7) & (5, 11)

= 2

The product of the gradients of two perpendicular lines is -1.

Gradient of the line that contains points (t, -2) & (-3, 5)

= -1 ÷2

Cross multiply:

-(t +3)= -7(2)

Dividing by -1 on both sides:

t +3= 7(2)

t +3= 14

t= 14 -3

t= 11

b

step-by-step explanation:

if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!

ok now , i would like brainlest plz