Jason ran for 5 miles. He ran the first 3 miles at an average rate of 8 miles per hour, and then he ran the final 2 miles at an average rate of 6 miles per hour. What is Jason’s average speed for the entire 5 miles?​

Step-by-step explanation:

jason ran the first 3 miles at 8mil/hr ie; so it took him 3/8 hrs to run 3 miles.

jason ran the final 2 miles at 6mil/hr ie; it took him 2/6 hrs to run 2 miles

the total time he took to run 5 miles will then be;

if we divide distance/time we get his speed/velocity;

ie, 5/(17/24) = 6.47mil/hr

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v