How to do this question??

h(2)= - 12

Step-by-step explanation:

What that means is: calculate the y-value when t=2. Where you see t, substitute 2 in the equation. y= - (2)^2 - 2(2) - 4

The answer is - 12

-12

Step-by-step explanation:

qu.   h(t) = -t^2 - 2t - 4

where h = 2

= h(t) = (-t^2)- (2^t)- (4)

= h(2) = (-2^2) - (2^2) - (4)

         = (-4) - (4) - (4)

          = -12

The way the brackets are done will help you when its mixed numbers and positives as the first polynomial if negative must be kept in bracket.

1/4 because there is 4 grades.