Help ill give u 25 points find the last digit of these numbers (and please explain why)

1)2^30
2)7^28
3)(5^2005)-5
4)(11^2005)-4^2005
5)(8^15)-3^7
6)3^75

Step-by-step explanation:

1) 2^1 = 2, 2^2=4, 2^3=8 2^4=6 2^5=2 .. we can find out a pattern: 2,4,8,6,2,4..

so 2^30 (mod 10) = 2^2 (mod 10) = 4

2) similar to Q1, 7^1 = 7, 7^2 = 9, 7^3 = 3, 7^4,=1, 7^5 = 7, the pattern is: 7,9,3,1,7.. so 7^28 = 7^4 = 1

3) since any power of 5 is equal to 5, (5^2005)-5 (mod 10) = 5-5 = 0

4) since any power of 1 is equal to 1, and there is a pattern for the power of 4 that is 4,6,4,6.. so (11^2005)-4^2005 = 1 - 4 (mod 10) = 7

5) 8's pattern is 8,4,2,6 and 3's pattern is 3,9,7,1, so (8^15)-3^7 = 2 - 7 = 5

6) 3's pattern is 3,9,7,1, so (3^75) (mod 10) = 7

4096 bacteria

step-by-step explanation:

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !