What is the equation of the line perpendicular to y = 5x +3 passing through the point (-3, 4)? y=x+
y-**3
y = -2r +3
23
T3
y = -2 -2
y = +5
Donen

y = x + 19

Step-by-step explanation:

Not sure what the stuff after "What is the equation of the line perpendicular to y = 5x +3 passing through the point (-3, 4)?" is, but I can create the equation from just that :D

So the equation will still be y = as it will be in slope intercept from (y=mx+b). The slope (m, or in this case currently it is 5) will change and be one-fifth as it is the opposite.

So far we have:

y = x + b

We then plug in the point (-3, 4) to figure out our b

(given) y = 5x + b

(plugging-in) 4 = 5(-3) + b

(mutiply) 4 = -15 + b

(adding 15 to both sides) 19 = b

Our equation will then be:

y = x + 19

Hopefully this is correct and helps, have a ncie day! :D

2: 10

step-by-step explanation:

answer: the center is the median and/or mean of the data. the spread is the range of the data. and, the shape describes the type of graph. the four ways to describe shape are whether it is symmetric, how many peaks it has, if it is skewed to the left or right, and whether it is uniform. good luck

step-by-step explanation: