Matter is in a Liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -38.17°C and a boiling point of 350 37°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C= 5/9(F-32)) Express the range as an inequality

Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?

(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as needed.)​

-35.626 < temperature < 733.928 . . . . degrees F

 (-35.626, 733.928)

Step-by-step explanation:

It is convenient to let a calculator evaluate the expression for converting °C to °F..

How this helps.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v