Find the x-intercept and y-intercept of the line . 7/3x - 1/3y = 1​

Step-by-step explanation:

The general equation of a line is y = mx+b

Rewrite the given equation (7/3)x -(1/3)y = 1 in the form of the general equation y=mx+b, where b is the y-intercept.

(7/3)x -(1/3)y = 1

-(1/3)y = -(7/3)x +1 , subtract (7/3)x from both sides

(1/3)y = (7/3)x -1 , multiplyed both sides by (-1)

y= 3(7/3)x -3, multiply both sides by 3

y= 7x -3, so

y-intercept is -3 or you can say that the y-intercept is at point (0, -3)

The x -intercept is at point (something, 0) so our y coordinate is 0 there

y= 7x -3, yet y=0 we said so substitute y with 0 in the equation and find x

0=7x-3 , add 3 to both sides

3= 7x, divide both sides by 7

3/7 = x

x-intercept is 3/7 or you can say that the x-intercept is at point (3/7, 0)

it would be 6xy and -16xy.

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