HUVILILAUOI PRUEBA DE PRE-GEOMETRÍA | LÍNEA BASE / 3 DE 40 ¿Con cuál de los siguientes conjuntos de figuras bidimensionales se puede formar un cubo? A. 3 rectángulos y 2 cuadrados O B. 4 triángulos y 1 cuadrado T) C. 4 cuadrados O D. 6 cuadrados​

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )

do you have a picture of the table

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

ιт ιѕ 12 αв

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