How can (a+3)^2=a^2+6a+9 be derived from the polynomial identity (a−3)^2=a^2−6a+9?

you would use (d.) the law of cosines or a^2 = b^2 + c^2 – 2bc(cos a)

, b^2 = a^2 + c^2 – 2ac(cos b), or c^2 = a^2 + b^2 - 2ab(cos c). you wouldn't use b. the law of sines as it is mostly effective when 1side and 2angles are given. a and c aren't the answer for they are the improper versions of the law of cosines. hope this is .

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

5/20 so 25%

step-by-step explanation: