How is 2x-3-(x+1) and -3+2x-(x+1) the same? (explain)​

|1–2x|≥3⇔∣∣x−12∣∣≥32

Since the two points at a distance 32 from 12 are 12+32=2 and 12−32=−1, points x whose distance from 12 is at least 32 are those that are either (i) on or to the left of −1 or (ii) on or to the right of 2.

In other words,

{x∈R:|1–2x|≥3}=(−∞,−1]⋃[2,∞). ■_

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