I'm doing a precal test right now please help find a slope-intercept form equation for the line.
through the points (1,6) and (-1,9)​

Since slope of line passing through two points (x

1

,y

1

) and (x

2

,y

2

) is m=

x

2

−x

1

y

2

−y

1

We now find the slope of the line passing through the points (2,3) and (4,6) as shown below:

m=

4−2

6−3

=

2

3

Therefore, the slope of the line is

2

3

.

Now use the slope and point (2,3) to find the y-intercept.

y=mx+b

⇒3=(

2

3

×2)+b

⇒3=3+b

⇒b=3−3=0

Write the equation in slope intercept form as:

y=mx+b

⇒y=

2

3

x+0

⇒y=

2

3

x

Hence, the equation of the line is y=

2

3

x..

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

i dont know

step-by-step explanation: