1. Ms. Mullins attaches herself to a strong bungee cord and jumps off a bridge. At time t = 3 sec, the comedy first becomes taut. From that time on, Mullins' distance, d feet, from the water below the bridge is given by the
following equation: d =-80(sin[1.2(t – 3)])+90. d=80(sin [1,2]) +90
How far is Mullins from the water when t = 4?

b. Find the average rate of change for the interval t= 3.9 to t = 4 sec, and for the interval t = 4 to
t= 4.1 sec.

c. Estimate the instantaneous rate of change at 4 sec.

e. Give the equation of the tangent line to the graph at 4 seconds.