Without graphing, describe the end behavior of the graph of the function. Ax) = 1-2x²x
As x, f(x) →-0.
As x →-00, f (x) > 0.
As x0, f (x) -0.
As x →-00, f (x) -→ -0.
As x, f(x) 0.
As x -00, f (x) → -0.
As x,(x) 0.
0$=
As x →-0 (x) > 00.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

idk

step-by-step explanation:

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point