You have $3000 to use for training your employees. Each hour of training costs a one
time fee of $200 and then $40 per employee
How many hours of training can you purchase?

Please solve using a system of equations (substitution or elimination)

Step-by-step explanation:

Total we have: 3000

Number of employees = x

Number of hours = y

The equation is:

3000 = (200 + 40y)x

We need to solve for y:

3000/x = 200 +40y

40y = 3000/x -200

Therefore, no. of hours =

the right system of equations to describe the situation would

be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of imogene and her

friend respectively at the end of t years.

now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

the solution is h=10 because you add 9 to each side of the equation.