Plz help! I don't understand these problems!

Find the value of x in each case.

1) x = 23

2) x = 14

Step by step explanation:

1)

∠ABD = ∠CBF (They are vertically opposite angles)

∠CBF = x

∠CBF = ∠BFE (They are alternate angles)

∠BFE = x

then

∠EBF + ∠BFE + ∠FEB = 180

(They are sum of angles of a triangle )

then substituting their values,

65 + x + 4x = 180

5x = 180 - 65

x = 115 ÷ 5

x = 23

2)

∠ACB + ∠FCB = 180 (Being a straight line)

∠ACB + 124 = 180

∠ACB = 180 - 124

∠ACB = 56

∠ABC + ∠EBA = 180 (Being a straight line)

∠ABC + 6x = 180

∠ABC = 180 - 6x

∠ABC + ∠ACB + ∠BAC = 180

(they are sum of angles of a triangle )

subsitituing values,

180 - 6x + 56 + 2x = 180

-4x = 180 - 236

x = - 56 ÷ - 4

x = 14

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