The expression (a + 1)x^3 + (2 – 3a)x^2 – (3a – 1)x + 2a – 13 has a factor x – 3. Find the value of a and
hence find the other two factors of the expression.​

the other two factors, (2x+1)(3x+1)

Step-by-step explanation:

(a + 1)x³ + (2 – 3a)x² – (3a – 1)x + 2a – 13 = 0   ...(1)

x-3 = 0     x = 3  

(a + 1)*3³ + (2 – 3a)*3² – (3a – 1)*3 + 2a – 13 = 0

-7a + 35 = 0

a = 5   .. substitute to (1)

6x³ -13x² – 14x -3 = 0

(x-3)(6x²+px+1) = 0 1*x * 6x² = 6x³,    -3 * 1 = -3

6x³ +(p-18)x² +(1-3p)x -3 = 0

p-18 = -13

p = 5

6x²+5x+1 = (2x+1)(3x+1)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values