575 tickets were sold for a game for a total of $675.00. If adult tickets sold for $1.50 and children's tickets sold for $1.00, how many of each kind of ticket were sold?

Adult is 200$ and children is 375$

Step-by-step explanation:

I. The clues we got are total tickets and total price.

adult price is 1.5$ and children price is 1$

Given a = adult and c = children

a + c = 575  => {total tickets}

1.5a + 1c = 675 => {total price}

II. Find a and c values by eliminate a or c

{total price} - {total tickes} will return to

(1.5a - 1a) + (1c - 1c) = 675 - 575

0.5a = 100

a = 200

III. Replace a value in {total tickets} will return to

200 + c = 575

c = 375

IV. Prove by replace a and c value in {total price}

200(1.5) + 375(1) = 675

300 + 375 = 675 true

That makes adult ticket is 200 and children ticket is 375.

Hope that help :)

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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