Find the point on the parabola y^2 = 8x at which the ordinate is double the abscissa.​

Step-by-step explanation:

Let's make a complex of functions

y^2 = 8x

y = 2x

Now let's solve it

(2x)^2 = 8x

4x^2 - 8x = 0

4x(x - 2) = 0

x = 0, 2

y = 0, 4

So the answer is (2, 4)

Hope you like it, study well

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

can you complete your sentence? i could !