Given g (x) = -2x^2 + 1, find the indicated values: g (0), g (-3), g (2), g (-4)

g(x) = -2x^2 + 1

In g(0), you're told x=0.  So you substitute 0 for x and simplify:

    g(0) = -2(0)^2 + 1

           = 1

In g(-3), you're told x=-3.  So you substitute -3 for x and simplify:

    g(-3) = -2(-3)^2 + 1

            = -17

In g(2), you're told x=2.  So you substitute 2 for x and simplify:

    g(2) = -2(2)^2 + 1

           = -7

In g(-4), you're told x=-4.  So you substitute -4 for x and simplify:

    g(-4) = -2(-4)^2 + 1

            = -31

0 is its x and y coordinate