a boat heads north at 30mph. A barge laves the same time from the same dock and heads east 40 mph. When is the distance between the boat and the barge 50 mi?

9514 1404 393

  after 1 hour

Step-by-step explanation:

One of the ways to solve this is to look at the separation of the boats after 1 hour. One is 30 miles north and the other is 40 miles east of the dock. The distance between them is the hypotenuse of the right triangle with legs 30 and 40 miles:

  d = √(30² +40²) = √(900 +1600) = √2500 = 50

The boats are 50 miles apart after 1 hour.

Additional comment

Had we been concerned with a different distance, we could use the separation speed of 50 mi/hour to determine the time.

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐