The midpoint of AB is M(7,-5). If the coordinates of A are (6,-7), what are the coordinates of B?

a(6,-7) m(7,-5) letb(p,q)

Now,

Let a(6,-7) be x1 ,y1

Let b(p,q) be x2,y2

x,y = (7,-5)

Using Mid point Formula,

x = x1+x2 y= y1+y2

,

2 2

7 = 6+p -5 = -7+q

___ ,

2 2

or, 7×2=6+p , -5×2= -7+q

or, 14=6+p , -10= -7+q

or, p=14-6 , q= -7+10

p=8 , q= 3

Step-by-step explanation:

So , The coordinate of B(8,3)

Thank you

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

12

step-by-step explanation: