What is the value of the expression 2x^3 y when x = -2 and y = 3?

Hey there!

2x^3y

= 2(-2)^3(3)

= 2(-3)^9

-2^9

= (-2)^9

= -2 * -2 * -2 * 2 * -2 * -2 * 2 * -2 * -2

= 4 * 4 * 4 * 4 * -2

= 16 * 16 * 2

= 256 * -2

= -512

= -2(-512)

= -1,024

Therefore, your answer is: -1,024

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

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step-by-step explanation: