A stadium has 54,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,151,000 from each sold-out event. How many seats does each section hold?

Section A = $27,000Section B = $14,800Section C = $12,200

Step-by-step explanation:

A: 27000 seats, B: 14200 seats, C: 12800 seats

Step-by-step explanation:

A + B + C = 54000

B + C = A

=> 2A = 54000 => A = 27000

=> B + C = 27000 => C = 27000 - B

25A + 20B + 15C = 1151000

25x27000 + 20B + 15(27000 - B) = 1151000

=> B = 14200

=> C = 27000 - 14200 = 12800

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.