A) gradient AB
+
b)
The line on the graph passes through the points A (0,6) and B (3,0).
YA
a) Calculate the gradient of line AB.
gradient perp.
+
C
Sub Anger
b) Find the gradient of a line perpendicular
to AB.
c) Find the equation of the line passing
through point A and perpendicular
to AB

easy math just plug in a and b

step-by-step explanation:

50

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.