Find the perimeter of quadrilateral A = (-4,3) C = (2,3) D = (4,-3) E = (-2,-3)

Step-by-step explanation:

Let A(–4,–2), B(–3,–5), C(3,–2) and D(2,3) be the vertices of the quadrilateral ABCD.

Area of a quadrilateral ABCD= Area of △ABC+ Area of △ACD

By using a formula for the area of a triangle =  

2

1

​

∣x  

1

​

(y  

2

​

−y  

3

​

)+x  

2

​

(y  

3

​

−y  

2

​

)+x  

3

​

(y  

1

​

−y  

2

​

)∣

Area of △ABC

=  

2

1

​

[−4(−5+2)+−3(−2+2)+3(−2+5)]

=  

2

1

​

[12+9]

=  

2

21

​

sq.units      

Area of △ACD=  

2

1

​

[−4(3+2)+−2(−2+2)+3(−2−3)]

=  

2

1

​

[−20−15]

=  

2

35

​

sq.units  

∴Area of quadilateral=  

2

21

​

+  

2

35

​  =  2/ 56  =28 sq.unit        

d. is the correct answer

step-by-step explanation:

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step-by-step explanation:

use that smart brain