What is the equation of a line parallel to y=-3x+5 that passes through point (6, 8)

5y = 6x + 4

Step-by-step explanation:

from the given equation we have to calculate y-intercept and the slope.

y= -3x+5

when x=1

y=-3(1)+5

y=-3+5 = 2

.: slope = (y₂-y₁)/(x₂-x₁)

slope= (8-2)/(6-1)

slope= m= 6/5

now the intercept

y = mx+b

8 = (6/5)(6) +b

8=36/5 + b

b = 8 - 36/5

b = (8×5 - 36)/5

b= (40-36)/5

b = 4/5

.: the slope-intercept formula

y=mx+b

y=(6/5)x + 4/5

y = (6x +4)/5

5y = 6x+4

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2