Here is a rule that can be used to build a sequence of numbers once a start number is chosen: Each number is two times three less than the previous a. starting with number 0, build a sequence of 5 numbers

b. starting with number 3, build a sequence of 5 numbers

c. can you choose a starting point so that the first 5 numbers in your sequence are all positive? explain your reasoning.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

grab rope, tie a loop-de-loop, put it around ur neck, now jump while its tied to a high place. now your shoes are cool.

step-by-step explanation:

step-by-step explanation:

im not sure what the answer is