Find the value kk that makes the function continuous. f(x)=\begin{cases} 10x-139, & x>7 \\ kx+8, & x\leq7 \end{cases}

f(x)={

10x−139,

kx+8,



x>7

x≤7

60 2(x + 2) in the diagram, gef and hef are congruent. what is the value of x?

Determine the required value of the missing probability to make the distribution a discrete probability distribution. x p(x) 3 0.23 4 ? 5 0.51 6 0.08 p(4) = nothing  (type an integer or a decimal.)

Ineed to know how to write question one in mathematical terms