1.Write an equation of the line that passes through the points (-3,-9) and (5. -9). 2. Write an equation in slope intercept form of the line that passes through the points (-2,10) and (5,-11)

Step-by-step explanation:

NUMBER ONE

The slope of tghe line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

                                           =  (- 9 - (-9)) ÷ ( 5 - (-3))

                                           =    0

The slope is zero because the y values of the line remain the same which means the line doesn't slope or rise.

We can now use the point-slope form to write the equation for this line:

y - y₁ = m(x - x₁)

            y - (-9) = 0 (x - (-3))

             y + 9  = 0

                   y  =  - 9

NUMBER TWO

For the slope-intercept form ( y = mx + c ) we need two main things: the slope (m) and the y-intercept (c)

slope = (y₂ - y₁) ÷ (x₂ - x₁)  = (10 - (-11)) ÷ (-2 - 5)

                                        =  21 ÷ (-7)

                                         = - 3

Let's write the equation without the value of c. This will help us solve for it.

                  y = -3x + c

if we substitute in a point give (-2 , 10) we can find c

                  10 = -3 (-2) + c

                   10 = 6 + c

                    c = 10 -6

                    c = 4

⇒ the equation of the line is y = -3x + 4

the least common denominator is 40

send it over

step-by-step explanation: