HELP PLEASE!!! Assume that when adults with smartphones are randomly selected, 59 % use them in meetings or classes. If 15 adult smartphone users are randomly selected, find the probability that exactly 10 of them use their smartphones in meetings or classes.
The probability is ?

5/10

Step-by-step explanation:

Let X will be the number of adults with smartphone which use them in meetings or classes.

X~Binomial(15, 0.59)

P(X=x) = C^{15}_x(0.59)^x(1-0.59)^{15-x}P(X=x)=C

x

15

(0.59)

x

(1−0.59)

15−x

You have to find the probability that exactly 10 of them use their smartphones in meetings or classes.

P(X=10) = C^{15}_{10} (0.59)^{10} (1-0.59)^{15-10} \\ = \frac{15!}{10!(15-10)!}(0.59)^{10}(0.41)^5 \\ = 3003 \times 0.00511 \times 0.01158 \\ = 0.17782P(X=10)=C

10

15

(0.59)

10

(1−0.59)

15−10

=

10!(15−10)!

15!

(0.59)

10

(0.41)

5

=3003×0.00511×0.01158

=0.17782

P=0.17782

required rate of return = 0.166 = 16.6%

step-by-step explanation:

under the capital asset pricing model (capm), the required or expected rate of return for a particular security or asset is given using the formula:

required rate of return = risk-free rate + beta*(market risk premium)

we are given that;

risk-free rate = 4% = 0.04

beta = 1.4

market risk premium = 9% = 0.09

we simply plug these values into the above formula;

required rate of return = 0.04 + 1.4*(0.09)

required rate of return = 0.04 + 0.126

required rate of return = 0.166 = 16.6%