Although a football field appears to be flat, some are actually shaped like a parabola so that rain runs off to both sides. The cross section of a field can be modeled by y = -0.000234x (20 160), where x and y are measured in feet. What is the width of the field? What is the maximum height of the surface of the field? Round your answers to the nearest tenth, if necessary. The width of the field is feet. The maximum height of the field is about fleet.

The ends of the field are at the zeros (x-intercept) of the function.

0 = -0.000234(x - 80)2 + 1.5      subtract 1.5 from both sides

-1.5 = -0.000234(x - 80)2           divide both sides by right coefficient

6410.25641 = (x - 80)2              take square root of both sides

80.064 = x - 80                         add 8-0 to both sides

160.064 = x

The field is 160.064 feet wide.  

The maximum is at the vertex, y = 1.5 feet

Step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).