5x2 – 2x - 3= 0 how do i solve this problem??

The solution set is {-3/5, 1}.

Step-by-step explanation:

5x^2 - 2x - 3 = 0

Use the 'ac' method.

We first multiply the first coefficient (5) by the the last one  (-3):

5 * -3 =-15.

Now e need 2 numbers whose product is -15 and whose sum = the middle coefficient in the equation (this is -2).

These numbers are -5 and + 3.

So we replace the -2x in the equation by -5x + 3x:-

5x^2 - 5x + 3x - 3 = 0

Now we factor by grouping:

5x(x - 1) + 3(x - 1) = 0

(x - 1) is common so:

(5x + 3)(x - 1) = 0

Giving x = -3/5 and x = 1.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

sorry i just need to anwers this to get points

step-by-step explanation: