What is the area of the figure below? A figure made up of a rectangle, a square, and a triangle all connected. The rectangle measures 4 centimeters by 8 centimeters. The square has side length 3 centimeters. The base of the triangle is one of the sides of the square and the height of the triangle is 8 minus 3 centimeters. A. 22 cm2 B. 24 cm2 C. 48.5 cm2 D. 56 cm2

48.5 cm

Step-by-step explanation:

Let's see the formulas for areas of the shapes

Rectangle = length * width

Square = side^2

Triangle = 1/2(base*height)

Let's calculate area of rectangle first since it's easiest

Length  = 8cm

Width = 4cm

8*4 = 32 cm

Now, let's get area of square.

3cm * 3cm = 9cm

Now, the triangle.

Because one side of the square is 3cm, all of its sides are 3cm, therefore the base of the triangle = 3cm

The height is 8-3 = 5cm

Area of triangle = 1/2(b*h) = 1/2(5*3) = 15/2= 7.5cm

Add up all the areas we got earlier...

Area of Shape = 32cm + 9cm + 7.5 cm = 48.5cm

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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answer: y=4000x+14000

step-by-step explanation: