Which ordered pairs are in the solution set of the system of linear inequalities?

The correct answer is the first option: (5, -2) (3, 1) (-4, 2)

Step-by-step explanation:

Given the following systems of linear inequalities:

y ≥ -1/2x and y < 1/2x + 1:

Plugging in the values of (5, -2) (3, 1) (-4, 2) into the given systems of linear inequalities provides a true statement:

y ≥ -1/2x:

(5, -2):  y ≥ -1/2x

          -2 ≥ -1/2(5)

          -2 ≥ -2.5  True statement.

(5, -2): y < 1/2x + 1

           -2 < 1/2(5) + 1

          -2 < 3.5  True statement.

(3, 1):  y ≥ -1/2x

         3 ≥ -1/2( 1 )

         3  ≥ -1/2 True statement.

(3, 1): y < 1/2x + 1

        1 < 1/2(3) + 1

        1 < 2.5  True statement.

(-4, 2): y ≥ -1/2x

          2 ≥ -1/2(-4)

         2  ≥ 2 True statement.

(-4, 2): y < 1/2x + 1

          2 < 1/2(-4) + 1

          2 < -1 True statement.

Therefore, (5, -2) (3, 1) (-4, 2) are the solutions to the systems of linear inequalities.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.